Base | Representation |
---|---|
bin | 110001101111001011… |
… | …001101110000000001 |
3 | 12002211212120212110021 |
4 | 301233023031300001 |
5 | 1333333113142213 |
6 | 40311150333441 |
7 | 3600264316051 |
oct | 615713156001 |
9 | 162755525407 |
10 | 53404818433 |
11 | 2071569a58a |
12 | a4251ba281 |
13 | 5061291aa5 |
14 | 28289d3561 |
15 | 15c874ed8d |
hex | c6f2cdc01 |
53404818433 has 2 divisors, whose sum is σ = 53404818434. Its totient is φ = 53404818432.
The previous prime is 53404818349. The next prime is 53404818457. The reversal of 53404818433 is 33481840435.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 32620694544 + 20784123889 = 180612^2 + 144167^2 .
It is a cyclic number.
It is not a de Polignac number, because 53404818433 - 213 = 53404810241 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 53404818433.
It is not a weakly prime, because it can be changed into another prime (53404818473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26702409216 + 26702409217.
It is an arithmetic number, because the mean of its divisors is an integer number (26702409217).
Almost surely, 253404818433 is an apocalyptic number.
It is an amenable number.
53404818433 is a deficient number, since it is larger than the sum of its proper divisors (1).
53404818433 is an equidigital number, since it uses as much as digits as its factorization.
53404818433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 552960, while the sum is 43.
The spelling of 53404818433 in words is "fifty-three billion, four hundred four million, eight hundred eighteen thousand, four hundred thirty-three".
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