Base | Representation |
---|---|
bin | 110001101111001101… |
… | …110001110001011111 |
3 | 12002211220212000001011 |
4 | 301233031301301133 |
5 | 1333333301142041 |
6 | 40311213000051 |
7 | 3600303114550 |
oct | 615715616137 |
9 | 162756760034 |
10 | 53405490271 |
11 | 20716009321 |
12 | a425483027 |
13 | 5061468823 |
14 | 2828b2a327 |
15 | 15c8833e81 |
hex | c6f371c5f |
53405490271 has 4 divisors (see below), whose sum is σ = 61034846032. Its totient is φ = 45776134512.
The previous prime is 53405490239. The next prime is 53405490277. The reversal of 53405490271 is 17209450435.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 17209450435 = 5 ⋅3441890087.
It is a cyclic number.
It is not a de Polignac number, because 53405490271 - 25 = 53405490239 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53405490277) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3814677870 + ... + 3814677883.
It is an arithmetic number, because the mean of its divisors is an integer number (15258711508).
Almost surely, 253405490271 is an apocalyptic number.
53405490271 is a deficient number, since it is larger than the sum of its proper divisors (7629355761).
53405490271 is an equidigital number, since it uses as much as digits as its factorization.
53405490271 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7629355760.
The product of its (nonzero) digits is 151200, while the sum is 40.
The spelling of 53405490271 in words is "fifty-three billion, four hundred five million, four hundred ninety thousand, two hundred seventy-one".
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