Base | Representation |
---|---|
bin | 110001101111100010… |
… | …110010111100110001 |
3 | 12002212022012221010101 |
4 | 301233202302330301 |
5 | 1333341204000423 |
6 | 40311531032401 |
7 | 3600401003332 |
oct | 615742627461 |
9 | 162768187111 |
10 | 53411000113 |
11 | 20719131a09 |
12 | a42729b701 |
13 | 50626476a3 |
14 | 2829762289 |
15 | 15c90717ad |
hex | c6f8b2f31 |
53411000113 has 2 divisors, whose sum is σ = 53411000114. Its totient is φ = 53411000112.
The previous prime is 53411000059. The next prime is 53411000119. The reversal of 53411000113 is 31100011435.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 34183572544 + 19227427569 = 184888^2 + 138663^2 .
It is a cyclic number.
It is not a de Polignac number, because 53411000113 - 217 = 53410869041 is a prime.
It is not a weakly prime, because it can be changed into another prime (53411000119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26705500056 + 26705500057.
It is an arithmetic number, because the mean of its divisors is an integer number (26705500057).
Almost surely, 253411000113 is an apocalyptic number.
It is an amenable number.
53411000113 is a deficient number, since it is larger than the sum of its proper divisors (1).
53411000113 is an equidigital number, since it uses as much as digits as its factorization.
53411000113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 180, while the sum is 19.
Adding to 53411000113 its reverse (31100011435), we get a palindrome (84511011548).
The spelling of 53411000113 in words is "fifty-three billion, four hundred eleven million, one hundred thirteen", and thus it is an aban number.
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