Base | Representation |
---|---|
bin | 11000010010011110001011… |
… | …00110111001101011100011 |
3 | 21000010001201201001200211221 |
4 | 30021033011212321223203 |
5 | 24000042201302310133 |
6 | 305332440524515511 |
7 | 14151556106044624 |
oct | 1411170546715343 |
9 | 230101651050757 |
10 | 53411233635043 |
11 | 16022638a60469 |
12 | 5ba75560abb97 |
13 | 23a587201b52b |
14 | d291905cda4b |
15 | 6295370dba2d |
hex | 3093c59b9ae3 |
53411233635043 has 2 divisors, whose sum is σ = 53411233635044. Its totient is φ = 53411233635042.
The previous prime is 53411233634959. The next prime is 53411233635061. The reversal of 53411233635043 is 34053633211435.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53411233635043 is a prime.
It is a super-2 number, since 2×534112336350432 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (53411233635143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26705616817521 + 26705616817522.
It is an arithmetic number, because the mean of its divisors is an integer number (26705616817522).
Almost surely, 253411233635043 is an apocalyptic number.
53411233635043 is a deficient number, since it is larger than the sum of its proper divisors (1).
53411233635043 is an equidigital number, since it uses as much as digits as its factorization.
53411233635043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1166400, while the sum is 43.
Adding to 53411233635043 its reverse (34053633211435), we get a palindrome (87464866846478).
The spelling of 53411233635043 in words is "fifty-three trillion, four hundred eleven billion, two hundred thirty-three million, six hundred thirty-five thousand, forty-three".
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