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5341127003 is a prime number
BaseRepresentation
bin1001111100101101…
…10010000101011011
3111210020021100211122
410332112302011123
541414312031003
62241554515455
7246233554562
oct47626620533
914706240748
105341127003
1122a0a21853
121050895b8b
136717291a4
143894dcbd9
15213d8b238
hex13e5b215b

5341127003 has 2 divisors, whose sum is σ = 5341127004. Its totient is φ = 5341127002.

The previous prime is 5341126991. The next prime is 5341127027. The reversal of 5341127003 is 3007211435.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5341127003 - 212 = 5341122907 is a prime.

It is not a weakly prime, because it can be changed into another prime (5341127063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2670563501 + 2670563502.

It is an arithmetic number, because the mean of its divisors is an integer number (2670563502).

Almost surely, 25341127003 is an apocalyptic number.

5341127003 is a deficient number, since it is larger than the sum of its proper divisors (1).

5341127003 is an equidigital number, since it uses as much as digits as its factorization.

5341127003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2520, while the sum is 26.

The square root of 5341127003 is about 73083.0144630064. The cubic root of 5341127003 is about 1748.0115649550.

Adding to 5341127003 its reverse (3007211435), we get a palindrome (8348338438).

The spelling of 5341127003 in words is "five billion, three hundred forty-one million, one hundred twenty-seven thousand, three".