Base | Representation |
---|---|
bin | 111100101110010101101110… |
… | …0101010100110001111111011 |
3 | 2121001012202022110100121220112 |
4 | 1321130223130222212033323 |
5 | 1030002224300301110022 |
6 | 5132001544541414535 |
7 | 220335636661355603 |
oct | 17134533452461773 |
9 | 2531182273317815 |
10 | 534134425019387 |
11 | 145212157082135 |
12 | 4baa69b626a44b |
13 | 19c0687748614a |
14 | 95c835bb9dc03 |
15 | 41b40dec228e2 |
hex | 1e5cadcaa63fb |
534134425019387 has 2 divisors, whose sum is σ = 534134425019388. Its totient is φ = 534134425019386.
The previous prime is 534134425019353. The next prime is 534134425019413. The reversal of 534134425019387 is 783910524431435.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 534134425019387 - 218 = 534134424757243 is a prime.
It is not a weakly prime, because it can be changed into another prime (534134424019387) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267067212509693 + 267067212509694.
It is an arithmetic number, because the mean of its divisors is an integer number (267067212509694).
Almost surely, 2534134425019387 is an apocalyptic number.
534134425019387 is a deficient number, since it is larger than the sum of its proper divisors (1).
534134425019387 is an equidigital number, since it uses as much as digits as its factorization.
534134425019387 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43545600, while the sum is 59.
The spelling of 534134425019387 in words is "five hundred thirty-four trillion, one hundred thirty-four billion, four hundred twenty-five million, nineteen thousand, three hundred eighty-seven".
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