Base | Representation |
---|---|
bin | 1111100010111001110… |
… | …11010101010100110001 |
3 | 1220001200210020111120022 |
4 | 13301130323111110301 |
5 | 32222402030034132 |
6 | 1045213410453225 |
7 | 53406235416002 |
oct | 7613473252461 |
9 | 1801623214508 |
10 | 534135002417 |
11 | 196586313aa5 |
12 | 87628894215 |
13 | 3b4a40b1c63 |
14 | 1bbd08c51a9 |
15 | dd6279ce12 |
hex | 7c5ced5531 |
534135002417 has 2 divisors, whose sum is σ = 534135002418. Its totient is φ = 534135002416.
The previous prime is 534135002383. The next prime is 534135002503. The reversal of 534135002417 is 714200531435.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 532602201616 + 1532800801 = 729796^2 + 39151^2 .
It is a cyclic number.
It is not a de Polignac number, because 534135002417 - 232 = 529840035121 is a prime.
It is not a weakly prime, because it can be changed into another prime (534135002617) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267067501208 + 267067501209.
It is an arithmetic number, because the mean of its divisors is an integer number (267067501209).
Almost surely, 2534135002417 is an apocalyptic number.
It is an amenable number.
534135002417 is a deficient number, since it is larger than the sum of its proper divisors (1).
534135002417 is an equidigital number, since it uses as much as digits as its factorization.
534135002417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50400, while the sum is 35.
The spelling of 534135002417 in words is "five hundred thirty-four billion, one hundred thirty-five million, two thousand, four hundred seventeen".
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