Base | Representation |
---|---|
bin | 111100101110111111001000… |
… | …0100010110001100100011011 |
3 | 2121001112020211020202002110112 |
4 | 1321131332100202301210123 |
5 | 1030010203401101312103 |
6 | 5132110452041434535 |
7 | 220345235302140443 |
oct | 17135762042614433 |
9 | 2531466736662415 |
10 | 534223342213403 |
11 | 145246935562047 |
12 | 4bb0009049ba4b |
13 | 19c12077b6790b |
14 | 95cc794d57123 |
15 | 41b6595eb2cd8 |
hex | 1e5df908b191b |
534223342213403 has 2 divisors, whose sum is σ = 534223342213404. Its totient is φ = 534223342213402.
The previous prime is 534223342213357. The next prime is 534223342213417. The reversal of 534223342213403 is 304312243322435.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 534223342213403 - 26 = 534223342213339 is a prime.
It is a super-3 number, since 3×5342233422134033 (a number of 45 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (534223342213423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267111671106701 + 267111671106702.
It is an arithmetic number, because the mean of its divisors is an integer number (267111671106702).
Almost surely, 2534223342213403 is an apocalyptic number.
534223342213403 is a deficient number, since it is larger than the sum of its proper divisors (1).
534223342213403 is an equidigital number, since it uses as much as digits as its factorization.
534223342213403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1244160, while the sum is 41.
Adding to 534223342213403 its reverse (304312243322435), we get a palindrome (838535585535838).
The spelling of 534223342213403 in words is "five hundred thirty-four trillion, two hundred twenty-three billion, three hundred forty-two million, two hundred thirteen thousand, four hundred three".
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