Base | Representation |
---|---|
bin | 1111100011000110101… |
… | …01001011010010001011 |
3 | 1220001222021101220200022 |
4 | 13301203111023102023 |
5 | 32223112031042311 |
6 | 1045232205331055 |
7 | 53412011550035 |
oct | 7614325132213 |
9 | 1801867356608 |
10 | 534242440331 |
11 | 196630a25766 |
12 | 87658866a8b |
13 | 3b4c042b0a2 |
14 | 1bc00c90c55 |
15 | dd6be215db |
hex | 7c6354b48b |
534242440331 has 2 divisors, whose sum is σ = 534242440332. Its totient is φ = 534242440330.
The previous prime is 534242440247. The next prime is 534242440349. The reversal of 534242440331 is 133044242435.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 534242440331 - 230 = 533168698507 is a prime.
It is a super-2 number, since 2×5342424403312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 534242440291 and 534242440300.
It is not a weakly prime, because it can be changed into another prime (534242470331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267121220165 + 267121220166.
It is an arithmetic number, because the mean of its divisors is an integer number (267121220166).
Almost surely, 2534242440331 is an apocalyptic number.
534242440331 is a deficient number, since it is larger than the sum of its proper divisors (1).
534242440331 is an equidigital number, since it uses as much as digits as its factorization.
534242440331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 138240, while the sum is 35.
Adding to 534242440331 its reverse (133044242435), we get a palindrome (667286682766).
The spelling of 534242440331 in words is "five hundred thirty-four billion, two hundred forty-two million, four hundred forty thousand, three hundred thirty-one".
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