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534311143 = 607880249
BaseRepresentation
bin11111110110001…
…111000011100111
31101020101211002121
4133312033003213
52043240424033
6125004050411
716145366302
oct3766170347
91336354077
10534311143
11254671963
1212ab33a07
1386909452
1450d67b39
1531d9462d
hex1fd8f0e7

534311143 has 4 divisors (see below), whose sum is σ = 535192000. Its totient is φ = 533430288.

The previous prime is 534311111. The next prime is 534311149. The reversal of 534311143 is 341113435.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 534311143 - 25 = 534311111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (534311149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 439518 + ... + 440731.

It is an arithmetic number, because the mean of its divisors is an integer number (133798000).

Almost surely, 2534311143 is an apocalyptic number.

534311143 is a deficient number, since it is larger than the sum of its proper divisors (880857).

534311143 is an equidigital number, since it uses as much as digits as its factorization.

534311143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 880856.

The product of its digits is 2160, while the sum is 25.

The square root of 534311143 is about 23115.1712734299. The cubic root of 534311143 is about 811.4555664984.

Adding to 534311143 its reverse (341113435), we get a palindrome (875424578).

The spelling of 534311143 in words is "five hundred thirty-four million, three hundred eleven thousand, one hundred forty-three".

Divisors: 1 607 880249 534311143