Base | Representation |
---|---|
bin | 11000010011000100001001… |
… | …11000101011100110111011 |
3 | 21000012000100122112010010210 |
4 | 30021202010320223212323 |
5 | 24000410430342112220 |
6 | 305350052031242203 |
7 | 14153210263360413 |
oct | 1411420470534673 |
9 | 230160318463123 |
10 | 53431622613435 |
11 | 16030251007730 |
12 | 5bab4a6379363 |
13 | 23a7771178ba1 |
14 | d2a16640b643 |
15 | 629d2c0906e0 |
hex | 309884e2b9bb |
53431622613435 has 128 divisors (see below), whose sum is σ = 100660443171840. Its totient is φ = 23926298572800.
The previous prime is 53431622613431. The next prime is 53431622613443.
53431622613435 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53431622613435 - 22 = 53431622613431 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53431622613431) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 25062205 + ... + 27110465.
It is an arithmetic number, because the mean of its divisors is an integer number (786409712280).
Almost surely, 253431622613435 is an apocalyptic number.
53431622613435 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53431622613435 is a deficient number, since it is larger than the sum of its proper divisors (47228820558405).
53431622613435 is a wasteful number, since it uses less digits than its factorization.
53431622613435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2048509.
The product of its digits is 4665600, while the sum is 48.
It can be divided in two parts, 5343162 and 2613435, that added together give a palindrome (7956597).
The spelling of 53431622613435 in words is "fifty-three trillion, four hundred thirty-one billion, six hundred twenty-two million, six hundred thirteen thousand, four hundred thirty-five".
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