Base | Representation |
---|---|
bin | 1001111100111110… |
… | …01011011110101001 |
3 | 111210101102012021022 |
4 | 10332133023132221 |
5 | 41420343000134 |
6 | 2242114022225 |
7 | 246261353144 |
oct | 47637133651 |
9 | 14711365238 |
10 | 5343328169 |
11 | 22a21955a3 |
12 | 1051577975 |
13 | 67201a05a |
14 | 38991305b |
15 | 21417352e |
hex | 13e7cb7a9 |
5343328169 has 2 divisors, whose sum is σ = 5343328170. Its totient is φ = 5343328168.
The previous prime is 5343328163. The next prime is 5343328217. The reversal of 5343328169 is 9618233435.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5230182400 + 113145769 = 72320^2 + 10637^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5343328169 is a prime.
It is a super-2 number, since 2×53433281692 = 57102311843257785122, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5343328163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2671664084 + 2671664085.
It is an arithmetic number, because the mean of its divisors is an integer number (2671664085).
Almost surely, 25343328169 is an apocalyptic number.
It is an amenable number.
5343328169 is a deficient number, since it is larger than the sum of its proper divisors (1).
5343328169 is an equidigital number, since it uses as much as digits as its factorization.
5343328169 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 466560, while the sum is 44.
The square root of 5343328169 is about 73098.0722659633. The cubic root of 5343328169 is about 1748.2516600499.
The spelling of 5343328169 in words is "five billion, three hundred forty-three million, three hundred twenty-eight thousand, one hundred sixty-nine".
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