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534334081 is a prime number
BaseRepresentation
bin11111110110010…
…100101010000001
31101020102222120011
4133312110222001
52043242142311
6125004344521
716145523211
oct3766245201
91336388504
10534334081
11254688116
1212ab45141
1386916a18
1450d72241
1531d9b321
hex1fd94a81

534334081 has 2 divisors, whose sum is σ = 534334082. Its totient is φ = 534334080.

The previous prime is 534334051. The next prime is 534334109. The reversal of 534334081 is 180433435.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 476330625 + 58003456 = 21825^2 + 7616^2 .

It is a cyclic number.

It is not a de Polignac number, because 534334081 - 225 = 500779649 is a prime.

It is a super-2 number, since 2×5343340812 = 571025820236229122, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (534334051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267167040 + 267167041.

It is an arithmetic number, because the mean of its divisors is an integer number (267167041).

Almost surely, 2534334081 is an apocalyptic number.

It is an amenable number.

534334081 is a deficient number, since it is larger than the sum of its proper divisors (1).

534334081 is an equidigital number, since it uses as much as digits as its factorization.

534334081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 31.

The square root of 534334081 is about 23115.6674357458. The cubic root of 534334081 is about 811.4671782728.

The spelling of 534334081 in words is "five hundred thirty-four million, three hundred thirty-four thousand, eighty-one".