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53435151119113 is a prime number
BaseRepresentation
bin11000010011001010101110…
…01100110111001100001001
321000012100110120000202222021
430021211113030313030021
524000440142141302423
6305351434115324441
714153363600233111
oct1411452714671411
9230170416022867
1053435151119113
11160317a1834225
125bb010bbb0721
1323a7bb41b627a
14d2a3bccaa041
15629e86c2d95d
hex309957337309

53435151119113 has 2 divisors, whose sum is σ = 53435151119114. Its totient is φ = 53435151119112.

The previous prime is 53435151119107. The next prime is 53435151119123. The reversal of 53435151119113 is 31191115153435.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 50993766744064 + 2441384375049 = 7140992^2 + 1562493^2 .

It is a cyclic number.

It is not a de Polignac number, because 53435151119113 - 241 = 51236127863561 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 53435151119113.

It is not a weakly prime, because it can be changed into another prime (53435151119123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26717575559556 + 26717575559557.

It is an arithmetic number, because the mean of its divisors is an integer number (26717575559557).

Almost surely, 253435151119113 is an apocalyptic number.

It is an amenable number.

53435151119113 is a deficient number, since it is larger than the sum of its proper divisors (1).

53435151119113 is an equidigital number, since it uses as much as digits as its factorization.

53435151119113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 121500, while the sum is 43.

The spelling of 53435151119113 in words is "fifty-three trillion, four hundred thirty-five billion, one hundred fifty-one million, one hundred nineteen thousand, one hundred thirteen".