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53440030551 = 317813343517
BaseRepresentation
bin110001110001010001…
…100010011101010111
312002221022211211101210
4301301101202131113
51333421121434201
640314445152503
73601202523225
oct616121423527
9162838754353
1053440030551
112073355aa06
12a434b5b733
13506867026b
14282d55bb15
1515cb8a81d6
hexc71462757

53440030551 has 4 divisors (see below), whose sum is σ = 71253374072. Its totient is φ = 35626687032.

The previous prime is 53440030531. The next prime is 53440030607. The reversal of 53440030551 is 15503004435.

53440030551 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-53440030551 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53440030531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8906671756 + ... + 8906671761.

It is an arithmetic number, because the mean of its divisors is an integer number (17813343518).

Almost surely, 253440030551 is an apocalyptic number.

53440030551 is a deficient number, since it is larger than the sum of its proper divisors (17813343521).

53440030551 is a wasteful number, since it uses less digits than its factorization.

53440030551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17813343520.

The product of its (nonzero) digits is 18000, while the sum is 30.

Adding to 53440030551 its reverse (15503004435), we get a palindrome (68943034986).

The spelling of 53440030551 in words is "fifty-three billion, four hundred forty million, thirty thousand, five hundred fifty-one".

Divisors: 1 3 17813343517 53440030551