Base | Representation |
---|---|
bin | 100110111000101100001… |
… | …1101000000011001101011 |
3 | 200220220220001100101012011 |
4 | 1031301120131000121223 |
5 | 1200030334332040201 |
6 | 15211105535300351 |
7 | 1061056535430532 |
oct | 115613035003153 |
9 | 20826801311164 |
10 | 5344423315051 |
11 | 17806146a5977 |
12 | 72395067a6b7 |
13 | 2c9c914ac6c2 |
14 | 14695871d319 |
15 | 94049da9151 |
hex | 4dc5874066b |
5344423315051 has 2 divisors, whose sum is σ = 5344423315052. Its totient is φ = 5344423315050.
The previous prime is 5344423314991. The next prime is 5344423315067. The reversal of 5344423315051 is 1505133244435.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5344423315051 - 215 = 5344423282283 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5344423314995 and 5344423315013.
It is not a weakly prime, because it can be changed into another prime (5344423312051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2672211657525 + 2672211657526.
It is an arithmetic number, because the mean of its divisors is an integer number (2672211657526).
Almost surely, 25344423315051 is an apocalyptic number.
5344423315051 is a deficient number, since it is larger than the sum of its proper divisors (1).
5344423315051 is an equidigital number, since it uses as much as digits as its factorization.
5344423315051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432000, while the sum is 40.
Adding to 5344423315051 its reverse (1505133244435), we get a palindrome (6849556559486).
The spelling of 5344423315051 in words is "five trillion, three hundred forty-four billion, four hundred twenty-three million, three hundred fifteen thousand, fifty-one".
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