Base | Representation |
---|---|
bin | 100110111000101101000… |
… | …0111000011010010001101 |
3 | 200220220221222122201100111 |
4 | 1031301122013003102031 |
5 | 1200030413441123000 |
6 | 15211112411200021 |
7 | 1061060323631434 |
oct | 115613207032215 |
9 | 20826858581314 |
10 | 5344451114125 |
11 | 1780629362812 |
12 | 723959a46011 |
13 | 2c9c97193966 |
14 | 14695c2b811b |
15 | 9404c54acba |
hex | 4dc5a1c348d |
5344451114125 has 8 divisors (see below), whose sum is σ = 6669874990584. Its totient is φ = 4275560891200.
The previous prime is 5344451114069. The next prime is 5344451114131. The reversal of 5344451114125 is 5214111544435.
It can be written as a sum of positive squares in 4 ways, for example, as 27124113636 + 5317327000489 = 164694^2 + 2305933^2 .
It is not a de Polignac number, because 5344451114125 - 213 = 5344451105933 is a prime.
It is a super-2 number, since 2×53444511141252 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21377804332 + ... + 21377804581.
It is an arithmetic number, because the mean of its divisors is an integer number (833734373823).
Almost surely, 25344451114125 is an apocalyptic number.
It is an amenable number.
5344451114125 is a deficient number, since it is larger than the sum of its proper divisors (1325423876459).
5344451114125 is an equidigital number, since it uses as much as digits as its factorization.
5344451114125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42755608928 (or 42755608918 counting only the distinct ones).
The product of its digits is 192000, while the sum is 40.
The spelling of 5344451114125 in words is "five trillion, three hundred forty-four billion, four hundred fifty-one million, one hundred fourteen thousand, one hundred twenty-five".
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