Base | Representation |
---|---|
bin | 100110111001000101010… |
… | …1011110110000011101101 |
3 | 200221000001210010112200010 |
4 | 1031302022223312003231 |
5 | 1200034101103100040 |
6 | 15211325322323433 |
7 | 1061116450616412 |
oct | 115621253660355 |
9 | 20830053115603 |
10 | 5345266065645 |
11 | 1780a07385970 |
12 | 723b46959579 |
13 | 2ca096c800ac |
14 | 1469d8616109 |
15 | 94098d77e80 |
hex | 4dc8aaf60ed |
5345266065645 has 32 divisors (see below), whose sum is σ = 9651640302720. Its totient is φ = 2502277111040.
The previous prime is 5345266065547. The next prime is 5345266065679. The reversal of 5345266065645 is 5465606625435.
It is not a de Polignac number, because 5345266065645 - 28 = 5345266065389 is a prime.
It is a super-3 number, since 3×53452660656453 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 558539214 + ... + 558548783.
It is an arithmetic number, because the mean of its divisors is an integer number (301613759460).
Almost surely, 25345266065645 is an apocalyptic number.
5345266065645 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
5345266065645 is a deficient number, since it is larger than the sum of its proper divisors (4306374237075).
5345266065645 is a wasteful number, since it uses less digits than its factorization.
5345266065645 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1117088045.
The product of its (nonzero) digits is 77760000, while the sum is 57.
The spelling of 5345266065645 in words is "five trillion, three hundred forty-five billion, two hundred sixty-six million, sixty-five thousand, six hundred forty-five".
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