Search a number
-
+
53463041358650 = 252711619208910739
BaseRepresentation
bin11000010011111110101011…
…00101101011101100111010
321000022000110021102202001222
430021333111211223230322
524001414302041434100
6305412325424112042
714155402001323610
oct1411772545535472
9230260407382058
1053463041358650
1116042604082a70
125bb55b4465622
1323aa70a4539a1
14d2b8a70476b0
1562aa6a513485
hex309fd596bb3a

53463041358650 has 192 divisors, whose sum is σ = 124250011776000. Its totient is φ = 16627372070400.

The previous prime is 53463041358647. The next prime is 53463041358733. The reversal of 53463041358650 is 5685314036435.

It is a junction number, because it is equal to n+sod(n) for n = 53463041358592 and 53463041358601.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 4978394981 + ... + 4978405719.

It is an arithmetic number, because the mean of its divisors is an integer number (647135478000).

Almost surely, 253463041358650 is an apocalyptic number.

53463041358650 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

53463041358650 is an abundant number, since it is smaller than the sum of its proper divisors (70786970417350).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

53463041358650 is a wasteful number, since it uses less digits than its factorization.

53463041358650 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13477 (or 13472 counting only the distinct ones).

The product of its (nonzero) digits is 15552000, while the sum is 53.

The spelling of 53463041358650 in words is "fifty-three trillion, four hundred sixty-three billion, forty-one million, three hundred fifty-eight thousand, six hundred fifty".