Base | Representation |
---|---|
bin | 110001110011010100… |
… | …110100000001001011 |
3 | 12010000201121011212111 |
4 | 301303110310001023 |
5 | 1334003424141324 |
6 | 40322114523151 |
7 | 3602101161112 |
oct | 616324640113 |
9 | 163021534774 |
10 | 53474443339 |
11 | 20750a24829 |
12 | a4445964b7 |
13 | 507282b965 |
14 | 2833d58c79 |
15 | 15ce904794 |
hex | c7353404b |
53474443339 has 2 divisors, whose sum is σ = 53474443340. Its totient is φ = 53474443338.
The previous prime is 53474443241. The next prime is 53474443361. The reversal of 53474443339 is 93334447435.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53474443339 - 229 = 52937572427 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53474443292 and 53474443301.
It is not a weakly prime, because it can be changed into another prime (53474443039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26737221669 + 26737221670.
It is an arithmetic number, because the mean of its divisors is an integer number (26737221670).
Almost surely, 253474443339 is an apocalyptic number.
53474443339 is a deficient number, since it is larger than the sum of its proper divisors (1).
53474443339 is an equidigital number, since it uses as much as digits as its factorization.
53474443339 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6531840, while the sum is 49.
The spelling of 53474443339 in words is "fifty-three billion, four hundred seventy-four million, four hundred forty-three thousand, three hundred thirty-nine".
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