535013040413 has 4 divisors (see below), whose sum is σ = 546396296640. Its totient is φ = 523629784188.

The previous prime is 535013040403. The next prime is 535013040421. The reversal of 535013040413 is 314040310535.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 535013040413 - 2¹⁰ = 535013039389 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (535013040403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5691628043 + ... + 5691628136.

It is an arithmetic number, because the mean of its divisors is an integer number (136599074160).

Almost surely, 2^535013040413 is an apocalyptic number.

It is an amenable number.

535013040413 is a deficient number, since it is larger than the sum of its proper divisors (11383256227).

535013040413 is a wasteful number, since it uses less digits than its factorization.

535013040413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11383256226.

The product of its (nonzero) digits is 10800, while the sum is 29.

Adding to 535013040413 its reverse (314040310535), we get a palindrome (849053350948).

The spelling of 535013040413 in words is "five hundred thirty-five billion, thirteen million, forty thousand, four hundred thirteen".