Search a number
-
+
53504101433 is a prime number
BaseRepresentation
bin110001110101000101…
…111100110000111001
312010002210101222010102
4301311011330300321
51334034022221213
640325054325145
73602611233626
oct616505746071
9163083358112
1053504101433
1120766741352
12a4524b97b5
135078a14123
142837c7934d
1515d2312158
hexc7517cc39

53504101433 has 2 divisors, whose sum is σ = 53504101434. Its totient is φ = 53504101432.

The previous prime is 53504101397. The next prime is 53504101459. The reversal of 53504101433 is 33410140535.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31956210169 + 21547891264 = 178763^2 + 146792^2 .

It is a cyclic number.

It is not a de Polignac number, because 53504101433 - 220 = 53503052857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53504101396 and 53504101405.

It is not a weakly prime, because it can be changed into another prime (53504101633) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26752050716 + 26752050717.

It is an arithmetic number, because the mean of its divisors is an integer number (26752050717).

Almost surely, 253504101433 is an apocalyptic number.

It is an amenable number.

53504101433 is a deficient number, since it is larger than the sum of its proper divisors (1).

53504101433 is an equidigital number, since it uses as much as digits as its factorization.

53504101433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10800, while the sum is 29.

Adding to 53504101433 its reverse (33410140535), we get a palindrome (86914241968).

The spelling of 53504101433 in words is "fifty-three billion, five hundred four million, one hundred one thousand, four hundred thirty-three".