Base | Representation |
---|---|
bin | 111100110101000110101111… |
… | …0001101011110111000011111 |
3 | 2121011111122111211120011121010 |
4 | 1321222031132031132320133 |
5 | 1030112443202202023210 |
6 | 5133553052401110303 |
7 | 220463056302015600 |
oct | 17152153615367037 |
9 | 2534448454504533 |
10 | 535064311361055 |
11 | 145540555735853 |
12 | 5001706b328393 |
13 | 19c7346a8c0a98 |
14 | 961b372485da7 |
15 | 41cd3b5dc6920 |
hex | 1e6a35e35ee1f |
535064311361055 has 48 divisors (see below), whose sum is σ = 997385991719040. Its totient is φ = 244229658136128.
The previous prime is 535064311360949. The next prime is 535064311361077. The reversal of 535064311361055 is 550163113460535.
It is not a de Polignac number, because 535064311361055 - 27 = 535064311360927 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 535064311360995 and 535064311361013.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 551851489 + ... + 552820218.
It is an arithmetic number, because the mean of its divisors is an integer number (20778874827480).
Almost surely, 2535064311361055 is an apocalyptic number.
535064311361055 is a deficient number, since it is larger than the sum of its proper divisors (462321680357985).
535064311361055 is a wasteful number, since it uses less digits than its factorization.
535064311361055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1104672388 (or 1104672381 counting only the distinct ones).
The product of its (nonzero) digits is 2430000, while the sum is 48.
The spelling of 535064311361055 in words is "five hundred thirty-five trillion, sixty-four billion, three hundred eleven million, three hundred sixty-one thousand, fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.088 sec. • engine limits •