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53511148441 is a prime number
BaseRepresentation
bin110001110101100000…
…110101001110011001
312010010021122222210201
4301311200311032121
51334042323222231
640325505342201
73603025154062
oct616540651631
9163107588721
1053511148441
112076a714923
12a454937961
13507a31085a
142838b91569
1515d2c55161
hexc75835399

53511148441 has 2 divisors, whose sum is σ = 53511148442. Its totient is φ = 53511148440.

The previous prime is 53511148429. The next prime is 53511148499. The reversal of 53511148441 is 14484111535.

53511148441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 53437257225 + 73891216 = 231165^2 + 8596^2 .

It is a cyclic number.

It is not a de Polignac number, because 53511148441 - 215 = 53511115673 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 53511148441.

It is not a weakly prime, because it can be changed into another prime (53511148241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26755574220 + 26755574221.

It is an arithmetic number, because the mean of its divisors is an integer number (26755574221).

Almost surely, 253511148441 is an apocalyptic number.

It is an amenable number.

53511148441 is a deficient number, since it is larger than the sum of its proper divisors (1).

53511148441 is an equidigital number, since it uses as much as digits as its factorization.

53511148441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 38400, while the sum is 37.

Adding to 53511148441 its reverse (14484111535), we get a palindrome (67995259976).

The spelling of 53511148441 in words is "fifty-three billion, five hundred eleven million, one hundred forty-eight thousand, four hundred forty-one".