Base | Representation |
---|---|
bin | 1100110000101… |
… | …0011010100101 |
3 | 10201201002200121 |
4 | 3030022122211 |
5 | 102200120122 |
6 | 5151041541 |
7 | 1216625044 |
oct | 314123245 |
9 | 121632617 |
10 | 53520037 |
11 | 2823543a |
12 | 15b102b1 |
13 | b11b67c |
14 | 717255b |
15 | 4a72bc7 |
hex | 330a6a5 |
53520037 has 4 divisors (see below), whose sum is σ = 53660160. Its totient is φ = 53379916.
The previous prime is 53520031. The next prime is 53520059. The reversal of 53520037 is 73002535.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 73002535 = 5 ⋅14600507.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53520037 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53519993 and 53520020.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53520031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69487 + ... + 70252.
It is an arithmetic number, because the mean of its divisors is an integer number (13415040).
Almost surely, 253520037 is an apocalyptic number.
It is an amenable number.
53520037 is a deficient number, since it is larger than the sum of its proper divisors (140123).
53520037 is a wasteful number, since it uses less digits than its factorization.
53520037 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 140122.
The product of its (nonzero) digits is 3150, while the sum is 25.
The square root of 53520037 is about 7315.7389920636. The cubic root of 53520037 is about 376.8531371946.
The spelling of 53520037 in words is "fifty-three million, five hundred twenty thousand, thirty-seven".
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