Base | Representation |
---|---|
bin | 11000010101101001100100… |
… | …11110000000101101110011 |
3 | 21000111111121002012100022121 |
4 | 30022310302132000231303 |
5 | 24003334322124003012 |
6 | 305454540440015111 |
7 | 14162503152420115 |
oct | 1412646236005563 |
9 | 230444532170277 |
10 | 53520434203507 |
11 | 16064985918857 |
12 | 6004751161497 |
13 | 23b2c55a0420b |
14 | d3058d5553b5 |
15 | 62c2c8e20a07 |
hex | 30ad32780b73 |
53520434203507 has 2 divisors, whose sum is σ = 53520434203508. Its totient is φ = 53520434203506.
The previous prime is 53520434203403. The next prime is 53520434203559. The reversal of 53520434203507 is 70530243402535.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53520434203507 - 211 = 53520434201459 is a prime.
It is not a weakly prime, because it can be changed into another prime (53520434203207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26760217101753 + 26760217101754.
It is an arithmetic number, because the mean of its divisors is an integer number (26760217101754).
Almost surely, 253520434203507 is an apocalyptic number.
53520434203507 is a deficient number, since it is larger than the sum of its proper divisors (1).
53520434203507 is an equidigital number, since it uses as much as digits as its factorization.
53520434203507 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512000, while the sum is 43.
The spelling of 53520434203507 in words is "fifty-three trillion, five hundred twenty billion, four hundred thirty-four million, two hundred three thousand, five hundred seven".
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