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535216335000097 is a prime number
BaseRepresentation
bin111100110110001101100001…
…1100001101001001000100001
32121012001011220121212012100211
41321230123003201221020201
51030122441023230000342
65134150553455214121
7220510050502435252
oct17154330341511041
92535034817765324
10535216335000097
11145599a78056963
1250040617817341
1319c848b74a319a
1496248748c6b29
1541d2312487c17
hex1e6c6c3869221

535216335000097 has 2 divisors, whose sum is σ = 535216335000098. Its totient is φ = 535216335000096.

The previous prime is 535216335000041. The next prime is 535216335000157. The reversal of 535216335000097 is 790000533612535.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 535157943177361 + 58391822736 = 23133481^2 + 241644^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-535216335000097 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 535216335000097.

It is not a weakly prime, because it can be changed into another prime (535216335000007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267608167500048 + 267608167500049.

It is an arithmetic number, because the mean of its divisors is an integer number (267608167500049).

Almost surely, 2535216335000097 is an apocalyptic number.

It is an amenable number.

535216335000097 is a deficient number, since it is larger than the sum of its proper divisors (1).

535216335000097 is an equidigital number, since it uses as much as digits as its factorization.

535216335000097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2551500, while the sum is 49.

The spelling of 535216335000097 in words is "five hundred thirty-five trillion, two hundred sixteen billion, three hundred thirty-five million, ninety-seven", and thus it is an aban number.