Base | Representation |
---|---|
bin | 11000010110010000110101… |
… | …10001010000000001100001 |
3 | 21000120111222222201101211210 |
4 | 30023020122301100001201 |
5 | 24004211003411231431 |
6 | 305512344130100333 |
7 | 14164150365040542 |
oct | 1413103261200141 |
9 | 230514888641753 |
10 | 53541511430241 |
11 | 160729114181aa |
12 | 6008853a1a6a9 |
13 | 23b4c34618003 |
14 | d315cc92c4c9 |
15 | 62cb0e524d46 |
hex | 30b21ac50061 |
53541511430241 has 32 divisors (see below), whose sum is σ = 74732859767808. Its totient is φ = 34060033163520.
The previous prime is 53541511430237. The next prime is 53541511430263. The reversal of 53541511430241 is 14203411514535.
It is not a de Polignac number, because 53541511430241 - 22 = 53541511430237 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 53541511430241.
It is not an unprimeable number, because it can be changed into a prime (53541511438241) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12096240 + ... + 15918606.
It is an arithmetic number, because the mean of its divisors is an integer number (2335401867744).
Almost surely, 253541511430241 is an apocalyptic number.
It is an amenable number.
53541511430241 is a deficient number, since it is larger than the sum of its proper divisors (21191348337567).
53541511430241 is a wasteful number, since it uses less digits than its factorization.
53541511430241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3824841.
The product of its (nonzero) digits is 144000, while the sum is 39.
Adding to 53541511430241 its reverse (14203411514535), we get a palindrome (67744922944776).
The spelling of 53541511430241 in words is "fifty-three trillion, five hundred forty-one billion, five hundred eleven million, four hundred thirty thousand, two hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •