Base | Representation |
---|---|
bin | 1111100101010101111… |
… | …10101011110111001101 |
3 | 1220012002001022002001102 |
4 | 13302222332223313031 |
5 | 32233042243112023 |
6 | 1045551345552445 |
7 | 53453546121626 |
oct | 7625276536715 |
9 | 1805061262042 |
10 | 535444504013 |
11 | 197098510a21 |
12 | 87933345725 |
13 | 3b652495983 |
14 | 1bcb679aa4d |
15 | dddc718628 |
hex | 7caafabdcd |
535444504013 has 4 divisors (see below), whose sum is σ = 535453243488. Its totient is φ = 535435764540.
The previous prime is 535444503953. The next prime is 535444504037. The reversal of 535444504013 is 310405444535.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 535444504013 - 212 = 535444499917 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (535444504073) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4277183 + ... + 4400588.
It is an arithmetic number, because the mean of its divisors is an integer number (133863310872).
Almost surely, 2535444504013 is an apocalyptic number.
It is an amenable number.
535444504013 is a deficient number, since it is larger than the sum of its proper divisors (8739475).
535444504013 is an equidigital number, since it uses as much as digits as its factorization.
535444504013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8739474.
The product of its (nonzero) digits is 288000, while the sum is 38.
Adding to 535444504013 its reverse (310405444535), we get a palindrome (845849948548).
The spelling of 535444504013 in words is "five hundred thirty-five billion, four hundred forty-four million, five hundred four thousand, thirteen".
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