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535445114103001 is a prime number
BaseRepresentation
bin111100110111111000000011…
…1110100101010010011011001
32121012212001102122002210021101
41321233300013310222103121
51030140213043202244001
65134444031205311401
7220532430036636334
oct17157600764522331
92535761378083241
10535445114103001
11145677aa7982023
1250078a25405561
1319ca0346c5741b
149631978c0361b
1541d825226da01
hex1e6fc07d2a4d9

535445114103001 has 2 divisors, whose sum is σ = 535445114103002. Its totient is φ = 535445114103000.

The previous prime is 535445114102993. The next prime is 535445114103037. The reversal of 535445114103001 is 100301411544535.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 505257067349776 + 30188046753225 = 22477924^2 + 5494365^2 .

It is a cyclic number.

It is not a de Polignac number, because 535445114103001 - 23 = 535445114102993 is a prime.

It is not a weakly prime, because it can be changed into another prime (535445114103041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267722557051500 + 267722557051501.

It is an arithmetic number, because the mean of its divisors is an integer number (267722557051501).

Almost surely, 2535445114103001 is an apocalyptic number.

It is an amenable number.

535445114103001 is a deficient number, since it is larger than the sum of its proper divisors (1).

535445114103001 is an equidigital number, since it uses as much as digits as its factorization.

535445114103001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72000, while the sum is 37.

Adding to 535445114103001 its reverse (100301411544535), we get a palindrome (635746525647536).

The spelling of 535445114103001 in words is "five hundred thirty-five trillion, four hundred forty-five billion, one hundred fourteen million, one hundred three thousand, one".