Base | Representation |
---|---|
bin | 111100110111111000000011… |
… | …1110100101010010011011001 |
3 | 2121012212001102122002210021101 |
4 | 1321233300013310222103121 |
5 | 1030140213043202244001 |
6 | 5134444031205311401 |
7 | 220532430036636334 |
oct | 17157600764522331 |
9 | 2535761378083241 |
10 | 535445114103001 |
11 | 145677aa7982023 |
12 | 50078a25405561 |
13 | 19ca0346c5741b |
14 | 9631978c0361b |
15 | 41d825226da01 |
hex | 1e6fc07d2a4d9 |
535445114103001 has 2 divisors, whose sum is σ = 535445114103002. Its totient is φ = 535445114103000.
The previous prime is 535445114102993. The next prime is 535445114103037. The reversal of 535445114103001 is 100301411544535.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 505257067349776 + 30188046753225 = 22477924^2 + 5494365^2 .
It is a cyclic number.
It is not a de Polignac number, because 535445114103001 - 23 = 535445114102993 is a prime.
It is not a weakly prime, because it can be changed into another prime (535445114103041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267722557051500 + 267722557051501.
It is an arithmetic number, because the mean of its divisors is an integer number (267722557051501).
Almost surely, 2535445114103001 is an apocalyptic number.
It is an amenable number.
535445114103001 is a deficient number, since it is larger than the sum of its proper divisors (1).
535445114103001 is an equidigital number, since it uses as much as digits as its factorization.
535445114103001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72000, while the sum is 37.
Adding to 535445114103001 its reverse (100301411544535), we get a palindrome (635746525647536).
The spelling of 535445114103001 in words is "five hundred thirty-five trillion, four hundred forty-five billion, one hundred fourteen million, one hundred three thousand, one".
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