Base | Representation |
---|---|
bin | 111100110111111000000011… |
… | …1110100101010010011101101 |
3 | 2121012212001102122002210022010 |
4 | 1321233300013310222103231 |
5 | 1030140213043202244041 |
6 | 5134444031205311433 |
7 | 220532430036636363 |
oct | 17157600764522355 |
9 | 2535761378083263 |
10 | 535445114103021 |
11 | 145677aa7982041 |
12 | 50078a25405579 |
13 | 19ca0346c57435 |
14 | 9631978c03633 |
15 | 41d825226da16 |
hex | 1e6fc07d2a4ed |
535445114103021 has 16 divisors (see below), whose sum is σ = 715491334260864. Its totient is φ = 356181156724224.
The previous prime is 535445114103001. The next prime is 535445114103037. The reversal of 535445114103021 is 120301411544535.
It is not a de Polignac number, because 535445114103021 - 213 = 535445114094829 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (535445114103001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 744289525 + ... + 745008581.
It is an arithmetic number, because the mean of its divisors is an integer number (44718208391304).
Almost surely, 2535445114103021 is an apocalyptic number.
It is an amenable number.
535445114103021 is a deficient number, since it is larger than the sum of its proper divisors (180046220157843).
535445114103021 is a wasteful number, since it uses less digits than its factorization.
535445114103021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1262660.
The product of its (nonzero) digits is 144000, while the sum is 39.
Adding to 535445114103021 its reverse (120301411544535), we get a palindrome (655746525647556).
The spelling of 535445114103021 in words is "five hundred thirty-five trillion, four hundred forty-five billion, one hundred fourteen million, one hundred three thousand, twenty-one".
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