Base | Representation |
---|---|
bin | 11000010110100111000010… |
… | …01011000010110101010001 |
3 | 21000121122202121122020220112 |
4 | 30023103201023002311101 |
5 | 24004404411040442223 |
6 | 305522034530451105 |
7 | 14165051630246144 |
oct | 1413234113026521 |
9 | 230548677566815 |
10 | 53553430015313 |
11 | 16077978121608 |
12 | 600b01b433a95 |
13 | 23b60b3945407 |
14 | d31ddd7d605b |
15 | 62d0aaa62778 |
hex | 30b4e12c2d51 |
53553430015313 has 2 divisors, whose sum is σ = 53553430015314. Its totient is φ = 53553430015312.
The previous prime is 53553430015247. The next prime is 53553430015321. The reversal of 53553430015313 is 31351003435535.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 51503688032449 + 2049741982864 = 7176607^2 + 1431692^2 .
It is a cyclic number.
It is not a de Polignac number, because 53553430015313 - 210 = 53553430014289 is a prime.
It is not a weakly prime, because it can be changed into another prime (53553430015343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26776715007656 + 26776715007657.
It is an arithmetic number, because the mean of its divisors is an integer number (26776715007657).
Almost surely, 253553430015313 is an apocalyptic number.
It is an amenable number.
53553430015313 is a deficient number, since it is larger than the sum of its proper divisors (1).
53553430015313 is an equidigital number, since it uses as much as digits as its factorization.
53553430015313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 607500, while the sum is 41.
The spelling of 53553430015313 in words is "fifty-three trillion, five hundred fifty-three billion, four hundred thirty million, fifteen thousand, three hundred thirteen".
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