Base | Representation |
---|---|
bin | 100110111101110110011… |
… | …1010100010101000110111 |
3 | 200221222111021122111211121 |
4 | 1031323230322202220313 |
5 | 1200221033012120043 |
6 | 15220141245244411 |
7 | 1061631245034043 |
oct | 115735472425067 |
9 | 20858437574747 |
10 | 5355504020023 |
11 | 1785290446593 |
12 | 725b23563707 |
13 | 2cb039053271 |
14 | 1472ca1db023 |
15 | 94497a8aded |
hex | 4deecea2a37 |
5355504020023 has 4 divisors (see below), whose sum is σ = 5355519013600. Its totient is φ = 5355489026448.
The previous prime is 5355504019937. The next prime is 5355504020039. The reversal of 5355504020023 is 3200204055535.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5355504020023 - 29 = 5355504019511 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5355504029023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6947598 + ... + 7679851.
It is an arithmetic number, because the mean of its divisors is an integer number (1338879753400).
Almost surely, 25355504020023 is an apocalyptic number.
5355504020023 is a deficient number, since it is larger than the sum of its proper divisors (14993577).
5355504020023 is a wasteful number, since it uses less digits than its factorization.
5355504020023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14993576.
The product of its (nonzero) digits is 90000, while the sum is 34.
Adding to 5355504020023 its reverse (3200204055535), we get a palindrome (8555708075558).
The spelling of 5355504020023 in words is "five trillion, three hundred fifty-five billion, five hundred four million, twenty thousand, twenty-three".
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