Base | Representation |
---|---|
bin | 111100111100010010101101… |
… | …1010000101010001101101011 |
3 | 2121022000002011211022200200111 |
4 | 1321320211123100222031223 |
5 | 1030230134202202342311 |
6 | 5140030534224515151 |
7 | 220624325602553125 |
oct | 17170453320521553 |
9 | 2538002154280614 |
10 | 536052104340331 |
11 | 14589146a061367 |
12 | 501565a517bab7 |
13 | 1a01565bb80027 |
14 | 96530bb5c2215 |
15 | 41e8e2ab27d21 |
hex | 1e7895b42a36b |
536052104340331 has 2 divisors, whose sum is σ = 536052104340332. Its totient is φ = 536052104340330.
The previous prime is 536052104340293. The next prime is 536052104340421. The reversal of 536052104340331 is 133043401250635.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 536052104340331 - 215 = 536052104307563 is a prime.
It is a super-2 number, since 2×5360521043403312 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (536052104344331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 268026052170165 + 268026052170166.
It is an arithmetic number, because the mean of its divisors is an integer number (268026052170166).
Almost surely, 2536052104340331 is an apocalyptic number.
536052104340331 is a deficient number, since it is larger than the sum of its proper divisors (1).
536052104340331 is an equidigital number, since it uses as much as digits as its factorization.
536052104340331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 388800, while the sum is 40.
Adding to 536052104340331 its reverse (133043401250635), we get a palindrome (669095505590966).
The spelling of 536052104340331 in words is "five hundred thirty-six trillion, fifty-two billion, one hundred four million, three hundred forty thousand, three hundred thirty-one".
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