Base | Representation |
---|---|
bin | 100111000000100001011… |
… | …1000111011011111100011 |
3 | 200222112022010112212222201 |
4 | 1032001002320323133203 |
5 | 1200314310244433121 |
6 | 15222530441314031 |
7 | 1062223363021123 |
oct | 116010270733743 |
9 | 20875263485881 |
10 | 5361241405411 |
11 | 1787765008101 |
12 | 727064a95917 |
13 | 2cb7418b0968 |
14 | 1476b21a8c83 |
15 | 946d15ebe91 |
hex | 4e042e3b7e3 |
5361241405411 has 2 divisors, whose sum is σ = 5361241405412. Its totient is φ = 5361241405410.
The previous prime is 5361241405397. The next prime is 5361241405417. The reversal of 5361241405411 is 1145041421635.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5361241405411 - 25 = 5361241405379 is a prime.
It is not a weakly prime, because it can be changed into another prime (5361241405417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2680620702705 + 2680620702706.
It is an arithmetic number, because the mean of its divisors is an integer number (2680620702706).
Almost surely, 25361241405411 is an apocalyptic number.
5361241405411 is a deficient number, since it is larger than the sum of its proper divisors (1).
5361241405411 is an equidigital number, since it uses as much as digits as its factorization.
5361241405411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 57600, while the sum is 37.
The spelling of 5361241405411 in words is "five trillion, three hundred sixty-one billion, two hundred forty-one million, four hundred five thousand, four hundred eleven".
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