Base | Representation |
---|---|
bin | 110001111011101011… |
… | …001101110111110101 |
3 | 12010101111012112022102 |
4 | 301323223031313311 |
5 | 1334300310043013 |
6 | 40344041311445 |
7 | 3605422010066 |
oct | 617353156765 |
9 | 163344175272 |
10 | 53614534133 |
11 | 20813009046 |
12 | a483495585 |
13 | 509586b414 |
14 | 28487c456d |
15 | 15dbd77d58 |
hex | c7bacddf5 |
53614534133 has 4 divisors (see below), whose sum is σ = 54861383808. Its totient is φ = 52367684460.
The previous prime is 53614534117. The next prime is 53614534139. The reversal of 53614534133 is 33143541635.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 53614534133 - 24 = 53614534117 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53614534139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 623424773 + ... + 623424858.
It is an arithmetic number, because the mean of its divisors is an integer number (13715345952).
Almost surely, 253614534133 is an apocalyptic number.
It is an amenable number.
53614534133 is a deficient number, since it is larger than the sum of its proper divisors (1246849675).
53614534133 is a wasteful number, since it uses less digits than its factorization.
53614534133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1246849674.
The product of its digits is 194400, while the sum is 38.
The spelling of 53614534133 in words is "fifty-three billion, six hundred fourteen million, five hundred thirty-four thousand, one hundred thirty-three".
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