Base | Representation |
---|---|
bin | 110001111100000000… |
… | …001011111011100101 |
3 | 12010101212112210212200 |
4 | 301330000023323211 |
5 | 1334303211444310 |
6 | 40344355205113 |
7 | 3605516513406 |
oct | 617400137345 |
9 | 163355483780 |
10 | 53620031205 |
11 | 20816123084 |
12 | a4852a6799 |
13 | 5096a44520 |
14 | 28494159ad |
15 | 15dc5b19c0 |
hex | c7c00bee5 |
53620031205 has 96 divisors (see below), whose sum is σ = 102173460480. Its totient is φ = 25852055040.
The previous prime is 53620031203. The next prime is 53620031239. The reversal of 53620031205 is 50213002635.
53620031205 is a `hidden beast` number, since 5 + 3 + 620 + 0 + 31 + 2 + 0 + 5 = 666.
53620031205 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 53620031205 - 21 = 53620031203 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53620031203) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 8525572 + ... + 8531858.
It is an arithmetic number, because the mean of its divisors is an integer number (1064306880).
Almost surely, 253620031205 is an apocalyptic number.
It is an amenable number.
53620031205 is a deficient number, since it is larger than the sum of its proper divisors (48553429275).
53620031205 is a wasteful number, since it uses less digits than its factorization.
53620031205 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6611 (or 6608 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 27.
The spelling of 53620031205 in words is "fifty-three billion, six hundred twenty million, thirty-one thousand, two hundred five".
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