Base | Representation |
---|---|
bin | 11000011000101010101100… |
… | …00110001001011011001001 |
3 | 21000212102012111122112202201 |
4 | 30030111112012021123021 |
5 | 24012034134423030401 |
6 | 310014324312400201 |
7 | 14203133315024506 |
oct | 1414252606113311 |
9 | 230772174575681 |
10 | 53624111142601 |
11 | 160a494884269a |
12 | 60208663a6061 |
13 | 23bc969221b5c |
14 | d355c6a724ad |
15 | 62ed45d68b01 |
hex | 30c5561896c9 |
53624111142601 has 2 divisors, whose sum is σ = 53624111142602. Its totient is φ = 53624111142600.
The previous prime is 53624111142583. The next prime is 53624111142727. The reversal of 53624111142601 is 10624111142635.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 37998890376976 + 15625220765625 = 6164324^2 + 3952875^2 .
It is a cyclic number.
It is not a de Polignac number, because 53624111142601 - 217 = 53624111011529 is a prime.
It is not a weakly prime, because it can be changed into another prime (53624111146601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26812055571300 + 26812055571301.
It is an arithmetic number, because the mean of its divisors is an integer number (26812055571301).
Almost surely, 253624111142601 is an apocalyptic number.
It is an amenable number.
53624111142601 is a deficient number, since it is larger than the sum of its proper divisors (1).
53624111142601 is an equidigital number, since it uses as much as digits as its factorization.
53624111142601 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34560, while the sum is 37.
The spelling of 53624111142601 in words is "fifty-three trillion, six hundred twenty-four billion, one hundred eleven million, one hundred forty-two thousand, six hundred one".
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