53641041300 has 432 divisors, whose sum is σ = 220660876800. Its totient is φ = 10559289600.

The previous prime is 53641041299. The next prime is 53641041329. The reversal of 53641041300 is 314014635.

53641041300 is a `hidden beast` number, since 5 + 3 + 641 + 0 + 4 + 13 + 0 + 0 = 666.

It is a super-2 number, since 2×53641041300² (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 1296331 + ... + 1337069.

Almost surely, 2^53641041300 is an apocalyptic number.

53641041300 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 53641041300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (110330438400).

53641041300 is an abundant number, since it is smaller than the sum of its proper divisors (167019835500).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

53641041300 is a wasteful number, since it uses less digits than its factorization.

53641041300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40796 (or 40786 counting only the distinct ones).

The product of its (nonzero) digits is 4320, while the sum is 27.

Adding to 53641041300 its reverse (314014635), we get a palindrome (53955055935).

The spelling of 53641041300 in words is "fifty-three billion, six hundred forty-one million, forty-one thousand, three hundred".