Base | Representation |
---|---|
bin | 110001111101010001… |
… | …010100100010000101 |
3 | 12010110100120101022120 |
4 | 301331101110202011 |
5 | 1334324133100401 |
6 | 40350435120153 |
7 | 3606165346014 |
oct | 617521244205 |
9 | 163410511276 |
10 | 53641300101 |
11 | 2082712a784 |
12 | a490443059 |
13 | 509b28037c |
14 | 284c190a7b |
15 | 15de3b3836 |
hex | c7d454885 |
53641300101 has 4 divisors (see below), whose sum is σ = 71521733472. Its totient is φ = 35760866732.
The previous prime is 53641300091. The next prime is 53641300133. The reversal of 53641300101 is 10100314635.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 53641300101 - 27 = 53641299973 is a prime.
It is a super-2 number, since 2×536413001012 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53641300201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8940216681 + ... + 8940216686.
It is an arithmetic number, because the mean of its divisors is an integer number (17880433368).
Almost surely, 253641300101 is an apocalyptic number.
It is an amenable number.
53641300101 is a deficient number, since it is larger than the sum of its proper divisors (17880433371).
53641300101 is a wasteful number, since it uses less digits than its factorization.
53641300101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17880433370.
The product of its (nonzero) digits is 1080, while the sum is 24.
Adding to 53641300101 its reverse (10100314635), we get a palindrome (63741614736).
The spelling of 53641300101 in words is "fifty-three billion, six hundred forty-one million, three hundred thousand, one hundred one".
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