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53643431295 = 3259531250867
BaseRepresentation
bin110001111101011001…
…011100110101111111
312010110111120122202200
4301331121130311333
51334330204300140
640350552522543
73606222433266
oct617531346577
9163414518680
1053643431295
11208283559a3
12a4910b0453
13509b84842c
14284c5875dd
1515de685030
hexc7d65cd7f

53643431295 has 24 divisors (see below), whose sum is σ = 93079589616. Its totient is φ = 28579786368.

The previous prime is 53643431267. The next prime is 53643431299. The reversal of 53643431295 is 59213434635.

It is not a de Polignac number, because 53643431295 - 25 = 53643431263 is a prime.

It is a super-2 number, since 2×536434312952 (a number of 22 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (45).

It is a self number, because there is not a number n which added to its sum of digits gives 53643431295.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53643431299) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 582549 + ... + 668318.

It is an arithmetic number, because the mean of its divisors is an integer number (3878316234).

Almost surely, 253643431295 is an apocalyptic number.

53643431295 is a deficient number, since it is larger than the sum of its proper divisors (39436158321).

53643431295 is a wasteful number, since it uses less digits than its factorization.

53643431295 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1251831 (or 1251828 counting only the distinct ones).

The product of its digits is 1166400, while the sum is 45.

The spelling of 53643431295 in words is "fifty-three billion, six hundred forty-three million, four hundred thirty-one thousand, two hundred ninety-five".

Divisors: 1 3 5 9 15 45 953 2859 4765 8577 14295 42885 1250867 3752601 6254335 11257803 18763005 56289015 1192076251 3576228753 5960381255 10728686259 17881143765 53643431295