Base | Representation |
---|---|
bin | 110001111101011001… |
… | …011100110101111111 |
3 | 12010110111120122202200 |
4 | 301331121130311333 |
5 | 1334330204300140 |
6 | 40350552522543 |
7 | 3606222433266 |
oct | 617531346577 |
9 | 163414518680 |
10 | 53643431295 |
11 | 208283559a3 |
12 | a4910b0453 |
13 | 509b84842c |
14 | 284c5875dd |
15 | 15de685030 |
hex | c7d65cd7f |
53643431295 has 24 divisors (see below), whose sum is σ = 93079589616. Its totient is φ = 28579786368.
The previous prime is 53643431267. The next prime is 53643431299. The reversal of 53643431295 is 59213434635.
It is not a de Polignac number, because 53643431295 - 25 = 53643431263 is a prime.
It is a super-2 number, since 2×536434312952 (a number of 22 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (45).
It is a self number, because there is not a number n which added to its sum of digits gives 53643431295.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53643431299) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 582549 + ... + 668318.
It is an arithmetic number, because the mean of its divisors is an integer number (3878316234).
Almost surely, 253643431295 is an apocalyptic number.
53643431295 is a deficient number, since it is larger than the sum of its proper divisors (39436158321).
53643431295 is a wasteful number, since it uses less digits than its factorization.
53643431295 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1251831 (or 1251828 counting only the distinct ones).
The product of its digits is 1166400, while the sum is 45.
The spelling of 53643431295 in words is "fifty-three billion, six hundred forty-three million, four hundred thirty-one thousand, two hundred ninety-five".
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