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53645060442341 = 148336173338127
BaseRepresentation
bin11000011001010001101101…
…10001011000100011100101
321000221102021111110020110002
430030220312301120203211
524012410040433123331
6310032111152511045
714204504415110234
oct1414506661304345
9230842244406402
1053645060442341
1116102819106655
12602493224b485
1323c19274948c4
14d36613068b1b
156306700ed9cb
hex30ca36c588e5

53645060442341 has 4 divisors (see below), whose sum is σ = 53681233781952. Its totient is φ = 53608887102732.

The previous prime is 53645060442331. The next prime is 53645060442377. The reversal of 53645060442341 is 14324406054635.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53645060442341 - 222 = 53645056248037 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53645060442331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18086667581 + ... + 18086670546.

It is an arithmetic number, because the mean of its divisors is an integer number (13420308445488).

Almost surely, 253645060442341 is an apocalyptic number.

It is an amenable number.

53645060442341 is a deficient number, since it is larger than the sum of its proper divisors (36173339611).

53645060442341 is a wasteful number, since it uses less digits than its factorization.

53645060442341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36173339610.

The product of its (nonzero) digits is 4147200, while the sum is 47.

Adding to 53645060442341 its reverse (14324406054635), we get a palindrome (67969466496976).

The spelling of 53645060442341 in words is "fifty-three trillion, six hundred forty-five billion, sixty million, four hundred forty-two thousand, three hundred forty-one".

Divisors: 1 1483 36173338127 53645060442341