Base | Representation |
---|---|
bin | 100111000010000010110… |
… | …0000011011100001000101 |
3 | 200222211201200110220202011 |
4 | 1032010011200123201011 |
5 | 1200343002133240401 |
6 | 15224230440414221 |
7 | 1062400321142212 |
oct | 116040540334105 |
9 | 20884650426664 |
10 | 5364506540101 |
11 | 17890900a9125 |
12 | 727816477371 |
13 | 2cbb421a6617 |
14 | 147901aaab09 |
15 | 948230b4451 |
hex | 4e10581b845 |
5364506540101 has 16 divisors (see below), whose sum is σ = 5917018521600. Its totient is φ = 4840860589488.
The previous prime is 5364506540093. The next prime is 5364506540123. The reversal of 5364506540101 is 1010456054635.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 5364506540101 - 23 = 5364506540093 is a prime.
It is a super-3 number, since 3×53645065401013 (a number of 39 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5364506540161) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25577061 + ... + 25785946.
It is an arithmetic number, because the mean of its divisors is an integer number (369813657600).
Almost surely, 25364506540101 is an apocalyptic number.
It is an amenable number.
5364506540101 is a deficient number, since it is larger than the sum of its proper divisors (552511981499).
5364506540101 is a wasteful number, since it uses less digits than its factorization.
5364506540101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51363288.
The product of its (nonzero) digits is 216000, while the sum is 40.
The spelling of 5364506540101 in words is "five trillion, three hundred sixty-four billion, five hundred six million, five hundred forty thousand, one hundred one".
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