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53645130373 = 523102571951
BaseRepresentation
bin110001111101011111…
…111011101010000101
312010110121202222110111
4301331133323222011
51334331123132443
640351053153021
73606243041002
oct617537735205
9163417688414
1053645130373
112082930649a
12a49178b771
13509bcc18c3
14284c8aa8a9
1515de8bd69d
hexc7d7fba85

53645130373 has 4 divisors (see below), whose sum is σ = 53747702848. Its totient is φ = 53542557900.

The previous prime is 53645130359. The next prime is 53645130377. The reversal of 53645130373 is 37303154635.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53645130373 - 217 = 53644999301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53645130377) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51285453 + ... + 51286498.

It is an arithmetic number, because the mean of its divisors is an integer number (13436925712).

Almost surely, 253645130373 is an apocalyptic number.

It is an amenable number.

53645130373 is a deficient number, since it is larger than the sum of its proper divisors (102572475).

53645130373 is a wasteful number, since it uses less digits than its factorization.

53645130373 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 102572474.

The product of its (nonzero) digits is 340200, while the sum is 40.

The spelling of 53645130373 in words is "fifty-three billion, six hundred forty-five million, one hundred thirty thousand, three hundred seventy-three".

Divisors: 1 523 102571951 53645130373