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53645299307 = 423491266743
BaseRepresentation
bin110001111101100000…
…100100111001101011
312010110122002120012022
4301331200210321223
51334331144034212
640351100535055
73606244343345
oct617540447153
9163418076168
1053645299307
1120829411406
12a49185148b
13509c050772
14284c912295
1515de903772
hexc7d824e6b

53645299307 has 4 divisors (see below), whose sum is σ = 53646608400. Its totient is φ = 53643990216.

The previous prime is 53645299283. The next prime is 53645299313. The reversal of 53645299307 is 70399254635.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53645299307 - 26 = 53645299243 is a prime.

It is a super-2 number, since 2×536452993072 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53645299507) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 591023 + ... + 675720.

It is an arithmetic number, because the mean of its divisors is an integer number (13411652100).

Almost surely, 253645299307 is an apocalyptic number.

53645299307 is a deficient number, since it is larger than the sum of its proper divisors (1309093).

53645299307 is a wasteful number, since it uses less digits than its factorization.

53645299307 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1309092.

The product of its (nonzero) digits is 6123600, while the sum is 53.

The spelling of 53645299307 in words is "fifty-three billion, six hundred forty-five million, two hundred ninety-nine thousand, three hundred seven".

Divisors: 1 42349 1266743 53645299307