Base | Representation |
---|---|
bin | 110001111101100000… |
… | …100100111001110001 |
3 | 12010110122002120012112 |
4 | 301331200210321301 |
5 | 1334331144034223 |
6 | 40351100535105 |
7 | 3606244343354 |
oct | 617540447161 |
9 | 163418076175 |
10 | 53645299313 |
11 | 20829411411 |
12 | a491851495 |
13 | 509c050778 |
14 | 284c91229b |
15 | 15de903778 |
hex | c7d824e71 |
53645299313 has 2 divisors, whose sum is σ = 53645299314. Its totient is φ = 53645299312.
The previous prime is 53645299283. The next prime is 53645299319. The reversal of 53645299313 is 31399254635.
53645299313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 45359202529 + 8286096784 = 212977^2 + 91028^2 .
It is a cyclic number.
It is not a de Polignac number, because 53645299313 - 218 = 53645037169 is a prime.
It is not a weakly prime, because it can be changed into another prime (53645299319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26822649656 + 26822649657.
It is an arithmetic number, because the mean of its divisors is an integer number (26822649657).
Almost surely, 253645299313 is an apocalyptic number.
It is an amenable number.
53645299313 is a deficient number, since it is larger than the sum of its proper divisors (1).
53645299313 is an equidigital number, since it uses as much as digits as its factorization.
53645299313 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2624400, while the sum is 50.
The spelling of 53645299313 in words is "fifty-three billion, six hundred forty-five million, two hundred ninety-nine thousand, three hundred thirteen".
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