Base | Representation |
---|---|
bin | 100111000010011101101… |
… | …1000111010101101110011 |
3 | 200222221001200111220000211 |
4 | 1032010323120322231303 |
5 | 1200401330044243103 |
6 | 15224500252324551 |
7 | 1062431606051464 |
oct | 116047330725563 |
9 | 20887050456024 |
10 | 5365410540403 |
11 | 1789504412a11 |
12 | 727a29173757 |
13 | 2cbc57570a44 |
14 | 147989b88d6b |
15 | 9487763136d |
hex | 4e13b63ab73 |
5365410540403 has 2 divisors, whose sum is σ = 5365410540404. Its totient is φ = 5365410540402.
The previous prime is 5365410540389. The next prime is 5365410540463. The reversal of 5365410540403 is 3040450145635.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5365410540403 - 237 = 5227971586931 is a prime.
It is a super-2 number, since 2×53654105404032 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5365410540463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2682705270201 + 2682705270202.
It is an arithmetic number, because the mean of its divisors is an integer number (2682705270202).
Almost surely, 25365410540403 is an apocalyptic number.
5365410540403 is a deficient number, since it is larger than the sum of its proper divisors (1).
5365410540403 is an equidigital number, since it uses as much as digits as its factorization.
5365410540403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432000, while the sum is 40.
The spelling of 5365410540403 in words is "five trillion, three hundred sixty-five billion, four hundred ten million, five hundred forty thousand, four hundred three".
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