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53670073441483 is a prime number
BaseRepresentation
bin11000011010000000010011…
…01010011001110011001011
321001000210211200211020201201
430031000021222121303023
524013312302300111413
6310051405200125031
714206351311102052
oct1415001152316313
9231023750736651
1053670073441483
1116112394311074
126029753006777
1323c40b25ccb05
14d37907037399
15631135edc9dd
hex30d009a99ccb

53670073441483 has 2 divisors, whose sum is σ = 53670073441484. Its totient is φ = 53670073441482.

The previous prime is 53670073441441. The next prime is 53670073441507. The reversal of 53670073441483 is 38414437007635.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53670073441483 is a prime.

It is not a weakly prime, because it can be changed into another prime (53670073441583) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26835036720741 + 26835036720742.

It is an arithmetic number, because the mean of its divisors is an integer number (26835036720742).

Almost surely, 253670073441483 is an apocalyptic number.

53670073441483 is a deficient number, since it is larger than the sum of its proper divisors (1).

53670073441483 is an equidigital number, since it uses as much as digits as its factorization.

53670073441483 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20321280, while the sum is 55.

The spelling of 53670073441483 in words is "fifty-three trillion, six hundred seventy billion, seventy-three million, four hundred forty-one thousand, four hundred eighty-three".