Base | Representation |
---|---|
bin | 1001111111110111… |
… | …10011011000001011 |
3 | 111212002002210002112 |
4 | 10333323303120023 |
5 | 41443101440333 |
6 | 2244342252535 |
7 | 250004631242 |
oct | 47773633013 |
9 | 14762083075 |
10 | 5367608843 |
11 | 2304969a73 |
12 | 105972714b |
13 | 67706ba0c |
14 | 38cc33959 |
15 | 21636c948 |
hex | 13fef360b |
5367608843 has 2 divisors, whose sum is σ = 5367608844. Its totient is φ = 5367608842.
The previous prime is 5367608797. The next prime is 5367608903. The reversal of 5367608843 is 3488067635.
5367608843 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5367608843 is a prime.
It is a super-2 number, since 2×53676088432 = 57622449382903597298, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5367608791 and 5367608800.
It is not a weakly prime, because it can be changed into another prime (5367602843) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2683804421 + 2683804422.
It is an arithmetic number, because the mean of its divisors is an integer number (2683804422).
Almost surely, 25367608843 is an apocalyptic number.
5367608843 is a deficient number, since it is larger than the sum of its proper divisors (1).
5367608843 is an equidigital number, since it uses as much as digits as its factorization.
5367608843 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2903040, while the sum is 50.
The square root of 5367608843 is about 73263.9668800427. The cubic root of 5367608843 is about 1750.8957420325.
The spelling of 5367608843 in words is "five billion, three hundred sixty-seven million, six hundred eight thousand, eight hundred forty-three".
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