Base | Representation |
---|---|
bin | 1010000000000111… |
… | …11101101110111001 |
3 | 111212020010111000201 |
4 | 11000003331232321 |
5 | 41444123422114 |
6 | 2244500202201 |
7 | 250032052114 |
oct | 50003755671 |
9 | 14766114021 |
10 | 5369748409 |
11 | 23060a0503 |
12 | 105a399361 |
13 | 67763a82c |
14 | 38d22d57b |
15 | 216641874 |
hex | 1400fdbb9 |
5369748409 has 2 divisors, whose sum is σ = 5369748410. Its totient is φ = 5369748408.
The previous prime is 5369748379. The next prime is 5369748413. The reversal of 5369748409 is 9048479635.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4616794809 + 752953600 = 67947^2 + 27440^2 .
It is a cyclic number.
It is not a de Polignac number, because 5369748409 - 215 = 5369715641 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5369748409.
It is not a weakly prime, because it can be changed into another prime (5369748509) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2684874204 + 2684874205.
It is an arithmetic number, because the mean of its divisors is an integer number (2684874205).
Almost surely, 25369748409 is an apocalyptic number.
It is an amenable number.
5369748409 is a deficient number, since it is larger than the sum of its proper divisors (1).
5369748409 is an equidigital number, since it uses as much as digits as its factorization.
5369748409 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6531840, while the sum is 55.
The square root of 5369748409 is about 73278.5671871387. The cubic root of 5369748409 is about 1751.1283508453.
The spelling of 5369748409 in words is "five billion, three hundred sixty-nine million, seven hundred forty-eight thousand, four hundred nine".
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